The answer would be the Third Option, "Never".
speed of current is 1.5 mi/hr
Answer:
let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h
speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr
Answer:
40.25 if my math is right
Step-by-step explanation:
Answer:
The domain is t ≥ 0
The range is D ≥ 0
Step-by-step explanation:
D(t) = 100t + d₀
t is the time measured in hours.
d₀ is the initial position of the train.
We can assume the distance they go is not negative so...
The domain is t ≥ 0
The range is D ≥ 0
3x + 9 = 90
3x = 90 - 9 = 81
x = 81/3 = 27
x = 27
