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3 years ago

The graph compares the ages of 100 randomly selected visitors at a beach in January and in July.

Mathematics

2 answers:

Nina [5.8K]3 years ago

7 0

Answer:

the answer is 20, just took the test

Step-by-step explanation:

Kipish [7]3 years ago

6 0

The plot for January places the median age at 40, so half of the surveyed group was over 40. That would be half of 100 people, or 50 people.

The plot for July places the upper quartile at age 40, so 1/4 of the surveyed group was over 40. That would be 1/4 of 100 people, or 25 people.

There were 50 - 25 = 25 more visitors over the age of 40 at the beach in January.

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lozanna [386]

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3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

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So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
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so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
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3 years ago

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Vitek1552 [10]

Answer:

Step-by-step explanation:

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3 years ago

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Murrr4er [49]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x^2+x-42\\\\\text{The sum of the zeroes is -1=-7+6 and the product is -42=-7*6.}\\\\\text{So, we can factorise.}\\\\x^2+x-42\\\\=x^2+7x-6x-42\\\\=x(x+7)-6(x+7)\\\\=(x+7)(x-6)$

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