Question

The area of a square 16/36sq foot how do u get side length of the sq?​

Answer 1

We know that, the area of a square with side being s, is given by s², so if we here assume our side of square whose area is (16/36) sq. foot being s, so we will be having :

${:\implies \quad \sf s^{2}=\dfrac{16}{36}}$

${:\implies \quad \sf s=\pm \sqrt{\dfrac{16}{36}}}$

But, as length can never be -ve, so we will be taking only +ve length, and if we solve further for s, it will yield ;

${:\implies \quad \sf s=\sqrt{\dfrac{16}{36}}}$

${:\implies \quad \sf s=\dfrac{\sqrt{16}}{\sqrt{36}}}$

${:\implies \quad \sf s=\dfrac46}$

${:\implies \quad \boxed{\bf{s=\dfrac{4}{6}=\dfrac{2}{3}}}}$

Well, you might be thinking that (2/3)² willn't give (16/36) rather it will give (4/9), so for this, I'm telling that (2/3) ≈ 0.66666...7 and (4/6) ≈ 0.66666...7, so it's just the same thing and also, (16/36) and (4/9) are just too the same thing, dividing the numerator and denominator of (16/36) will just lead to (4/9) as same as (2/3)²