What are the solutions of 3x2 + 6x + 6 = 0
–2 ± i
–2 ± 2i
–1 ± i
1 ± i
1 answer:
C) Quick way:
3x^2+6x+6=0 ---> x^2+2x+2=0,
sum of solutions is the 'x' coefficient multiplied by -1: (-1+i)+(-1-i)=-2-->2
Product is the independent term: (-1+i)(=1+i) = (-1)^2-i^2 = 1+1=2
Takes longer to write it down!
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Answer:
No, because when j = 8, the values of the expressions are different.
Step-by-step explanation:
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