Answer:
(A) Set A is linearly independent and spans
. Set is a basis for
.
Step-by-Step Explanation
<u>Definition (Linear Independence)</u>
A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.
<u>Definition (Span of a Set of Vectors)</u>
The Span of a set of vectors is the set of all linear combinations of the vectors.
<u>Definition (A Basis of a Subspace).</u>
A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.
Given the set of vectors
, we are to decide which of the given statements is true:
In Matrix
, the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column.
has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans
.
Therefore Set A is linearly independent and spans
. Thus it is basis for
.
Answer:
96.04 ft
Step-by-step explanation:
nutiply 9. 8 by 9.8
The area of that figure is 2453.25 square feet
First, you would need to find the area of the rectangle
(L)(W)
(70)(30)
2100
Then since it is only a semi circle, the formula is pi*r^2/2
You find the area of a full circle first
(3.14)(15^2)
(3.14)(225)
706.5
Then you divide that by 2 since it’s only half a circle
706.5/2 = 353.25
Finally you add that by the area of the rectangle
2100 + 353.25 = 2453.25 square feet
(0,0), (3,0), (-6,0), and (7,0)
If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.
The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.
Conclusion: The function floor(x) is <u>not</u> periodic.