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stiks02 [169]
3 years ago
5

Hello can someone please help me ??? Solve the following system of equations graphically on the set of axes ?? y=2/3x+3 ........

...........................................................y=- 4/3-3 both of them on graph Please. ...
Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

keeping in mind that the solution to a system of equations is where the graphs of the equations meet or intersect, Check the picture below.

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Determine A:B:C, if A:B= 2:3 and B:C =4: 5​
cestrela7 [59]
I’m confused what we are suppose to do
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3 years ago
Limit as x approaches infinity: 2x/(3x²+5)
Nonamiya [84]
\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\implies \cfrac{\lim\limits_{x\to \infty}~2x}{\lim\limits_{x\to \infty}~3x^2+5}

now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

now, we could just use L'Hopital rule to check on that.

\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.
5 0
3 years ago
Square root of 0.925
shtirl [24]

Answer:

0.9617

Step-by-step explanation:

√0.925

= 0.9617

8 0
3 years ago
Read 2 more answers
What equation is ALWAYS TRUE?<br> HELPPPPPP
nadezda [96]

Answer:

2(x-1)=2x-2

Step-by-step explanation:

distribute the 2 into (x-1) so you get 2x-2 which is equal to 2x-2

3 0
4 years ago
Ivy is trying to manage the money she spends on lunch. Between eating out and buying groceries for bagged lunches, she wants to
mr_godi [17]

Answer:

The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:

x + 2x < 50 ............................ (2)

We can now solve for x as follows:

3x + < 50

x < 50 / 3

x < 16.67

Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

y < 2 * 16.67

y < 33.33

Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

7 0
3 years ago
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