Question

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Answer 1

Answer:

$\hookrightarrow \: u = 3 || \: a = - 12 \: || t = \frac{1}{3} \\ \hookrightarrow \: s = ut + \frac{1}{2} a {t}^{2} \\ \hookrightarrow \: s =3 \times \frac{1}{3} + \frac{1}{2} \times - 12 \times (\frac{1}{3} )^{2} \\ \hookrightarrow \: s =1 - \frac{2}{3} \\ \hookrightarrow \: s = \frac{1}{3}$

Answer 2

Answer:

s = $\frac{1}{3}$

Step-by-step explanation:

s = ut + $\frac{1}{2}$ at² ( substitute the given values into the equation )

s = ( 3 × $\frac{1}{3}$ ) + ( $\frac{1}{2}$ × - 12 × ($\frac{1}{3}$ )² )

  = 1 + (- 6 × $\frac{1}{9}$ )

  = 1 + ( - $\frac{2}{3}$ )

  = 1 - $\frac{2}{3}$

  = $\frac{1}{3}$