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mamaluj [8]
3 years ago
9

What is radio play ?

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0
The answer is A a play meant to be heard not seen.
Delvig [45]3 years ago
4 0
My answer would be a. a radio play is<span> the art of performing stories, acts, or even full-lengths musicals to be broadcast on radios. so baiscly u can really see them at all.</span>
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WILL GIVE A BRAINLEST
MAXImum [283]
The answer is B. <span>Two lines are perpendicular if they meet at one point and one of the angles at their point of intersection is a right angle. A perpendicular line has to intersect and have a 90-degree angle in order to be perpendicular.</span>
6 0
3 years ago
Read 2 more answers
A circle has an arc of length 20π that is intercepted by a central angle of 180°. What is the radius of the circle?
Bond [772]

Answer:

10π

Step-by-step explanation:

RULE:  The angle measure of the central angle is congruent to the measure of the intercepted arc.  

RULE:  Central Angle = Arc length

Given:  

Arc length (20 π) = central angle (180)

we know 180 degrees is a straight line, thus a semi-circle is created.  This would be the diameter.  

1/2 diameter is the radius.  20π/2 is the radius.  

10π

8 0
3 years ago
You and your friend are selling magazine subscriptions for a fundraiser. After w weeks, you have sold (7w+6) subscriptions and y
Mariulka [41]
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5 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
Which expression is equivalent to<br> (q^6)^2<br> q3<br> q8<br> q12<br> q36
Zepler [3.9K]
I think it’s q12 or C hope this helped
8 0
2 years ago
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