Answer:
Open a form in Google Forms.
In the top right, click More .
Click Add collaborators.
Under "Invite people," type the names or email addresses of the people you want to work with.
Click Send.
True
the Articles of Confederation are finally ratified. The Articles were signed by Congress and sent to the individual states for ratification on November 15, 1777, after 16 months of debate. Bickering over land claims between Virginia and Maryland delayed final ratification for almost four more years. Maryland finally approved the Articles on March 1, 1781, affirming the Articles as the outline of the official government of the United States. The nation was guided by the Articles of Confederation until the implementation of the current U.S. Constitution in 1789.
Answer:
normaly a CompTIA A+ and a Cisco CCNA
Explanation:
thses are just some of the basic's i seen comptia list with most network certifications.
Answer:
ababababab
Explanation:
The code above is written in python and python uses indentation .So let me rephrase the code accordingly and explain what the code really do.
Note x and y is a global variable which can be used by any of the function declared. According to the question x and y are 2 and 3 respectively
The first block of code describes a function f1 without any argument but the code should return the string "ab"
def f1():
return "ab"
The second block of code defines a function f2 and returns the value of f1 multiply by x. This means you are multiplying the string "ab" by 2 which will be equals to abab
def f2():
return f1() * x
The third block of code declared a function f3 and returns the sum of f2 and product of f1 and y. using PEMDAS principle the multiplication aspect will be solved first so, ab × 3 = ababab, then we add it to f2 . ababab + abab = ababababab.
def f3():
return f2() + f1() * y
Finally, we print the function f3 value to get ababababab
print(f3())
If you run the code on your IDE like below you will get ababababab
x = 2
y = 3
def f1():
return "ab"
def f2():
return f1() * x
def f3():
return f2() + f1() * y
print(f3())
