Https://www.toptal.com/bitcoin/blockchain-technology-powering-bitcoin
i dont have the time to read it right now, but i was able to find you this link that should hopefully help- you out!
Navigation items are used for moving from one part of the part to a destination using actions and also for passing information. The right option is <em>C. In the navigation menu and the first four items of the </em><em>navigation bar</em><em>, when users are in the app </em>
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There are different methods/ways to implement the Navigation component in a mobile application, we have the following type of Navigation Implementation
- Bottom Navigation
- Drawer Navigation(Slides from Left to right)
- Top Navigation
Learn more about Navigation here:
brainly.com/question/8908486
Answer:
I think this might help, don't know much of this
Explanation:
How do you calculate 3.5 increase in Excel?
How To Increase a Number By a Percentage. If want to calculate a percentage increase in Excel (i.e. increase a number by a specified percentage), this can be done by simply multiply the number by 1 + the percentage increase. - which gives the result 60.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]