Question

The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in slope-intercept form.

Answer 1

Answer:

y=-5x-2

Solution:

• We are given the line's slope and a point that it passes through.
• Using the given information, we can write the equation of the line in Point-Slope Form:
• $y-y_1=m(x-x_1)$
• In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
• In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
• Plug in the values:
• y-(-12)=-5(x-2)
• y+12=-5(x-2)
• Now, convert into Slope-Intercept Form, y=mx+b:
• y+12=-5x+10
• y=-5x+10-12
• y=-5x-2

Hope it helps.

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