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zhannawk [14.2K]
2 years ago
13

The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in sl

ope-intercept form.
Mathematics
1 answer:
DerKrebs [107]2 years ago
5 0
<h3>Answer:</h3>

y=-5x-2

<h3>Solution:</h3>
  • We are given the line's slope and a point that it passes through.
  • Using the given information, we can write the equation of the line in Point-Slope Form:
  • y-y_1=m(x-x_1)
  • In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
  • In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
  • Plug in the values:
  • y-(-12)=-5(x-2)
  • y+12=-5(x-2)
  • Now, convert into Slope-Intercept Form, y=mx+b:
  • y+12=-5x+10
  • y=-5x+10-12
  • y=-5x-2

Hope it helps.

Do comment if you have any query.

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You forgot to put the correct area model, I attached it to the answer.

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What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4
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<span>The equation is:   4x + y + a = 0

Point (4, -3)  </span>⇒  x = 4  and  y = - 3<span>

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</span>Ansver:   equation is:   4x + y - 13 = <span>0     OR     4x + y = 13
</span>


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