The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in sl

Question

2 years ago

13

ope-intercept form.

1 answer:

DerKrebs [107] · Answer 1 · 2023-01-06T13:42:15+03:00

<h3>Answer:</h3>

y=-5x-2

<h3>Solution:</h3>

We are given the line's slope and a point that it passes through.
Using the given information, we can write the equation of the line in Point-Slope Form:
$y-y_1=m(x-x_1)$
In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
Plug in the values:
y-(-12)=-5(x-2)
y+12=-5(x-2)
Now, convert into Slope-Intercept Form, y=mx+b:
y+12=-5x+10
y=-5x+10-12
y=-5x-2

Hope it helps.

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