Answer:
1. I am not sure about the first one. I tried everything and nothing I got from any of my work is looking right.
2. AB = 5
3. 8
Answer:
Plug in your x value into your equation --> y=2x+3
Step-by-step explanation:
Do this for each x-value that's missing the y- value :)
Answer:
x = 14
2x = 28
6x = 84
Step-by-step explanation:
6x = 180 - 124 + 2x
4x = 56
x = 14
see the attached figure to better understand the problem
we have that
![cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B1%7D%7B5%7D%20%5C%5C%20AB%3D12%5C%20units%5C%5C%20CD%3D2%5C%20units)
Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC
![cos (A)=(AC/AB)\\AC=AB*cos(A)](https://tex.z-dn.net/?f=cos%20%28A%29%3D%28AC%2FAB%29%5C%5CAC%3DAB%2Acos%28A%29)
substitute the values in the formula
![AC=12*(1/5)\\ AC=2.4\ units](https://tex.z-dn.net/?f=AC%3D12%2A%281%2F5%29%5C%5C%20AC%3D2.4%5C%20units)
Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem
![AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}](https://tex.z-dn.net/?f=AB%5E%7B2%7D%20%3DAC%5E%7B2%7D%2BBC%5E%7B2%7D%5C%5C%20BC%5E%7B2%7D%3DAB%5E%7B2%7D%20-AC%5E%7B2%7D)
substitute the values
![BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units](https://tex.z-dn.net/?f=BC%5E%7B2%7D%3D12%5E%7B2%7D%20-2.4%5E%7B2%7D%5C%5CBC%5E%7B2%7D%3D%20138.24%5C%5C%20BC%3D11.76%5C%20units)
Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem
![BD^{2} =DC^{2}+BC^{2}](https://tex.z-dn.net/?f=BD%5E%7B2%7D%20%3DDC%5E%7B2%7D%2BBC%5E%7B2%7D)
substitute the values
![BD^{2} =2^{2}+11.76^{2}](https://tex.z-dn.net/?f=BD%5E%7B2%7D%20%3D2%5E%7B2%7D%2B11.76%5E%7B2%7D)
![BD=11.93\ units](https://tex.z-dn.net/?f=BD%3D11.93%5C%20units)
therefore
<u>the answer is</u>
the length of BD is 11.93 units