Answer:
256
Step-by-step explanation:
4^4^4 = 4^(4^4) = 4^256
so written in base 4, there will be 256 zeroes after a 1.
This translates to approximately 154 digits in decimal.
Just like 2^2^2 = 2^4
there will be four zeroes after a 1.
2^2^2=2^(2^2) = 2^4 = 16 = 10000 (16 in base 2).
<h3>Answer: angle T = 70</h3>
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Work Shown:
Quadrilateral RSTU is a kite. In geometry, any kite has two pairs of adjacent congruent sides. In this case, RU = RS is one pair of adjacent congruent sides (single tickmarks), while TU = TS is the other pair of adjacent congruent sides (double tickmarks).
Draw diagonal line segment TR. This forms triangles TUR and TSR.
Through the SSS (side side side) congruence theorem, we can prove that the two triangles TUR and TSR are congruent.
Then by CPCTC (corresponding parts of congruent triangles are congruent), we can say,
angle U = angle S = 90
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Re-focus back on quadrilateral RSTU (ignore or erase line segment TR). The four angles of any quadrilateral will always add to 360 degrees. Let x be the measure of angle T.
(angleU)+(angleR)+(angleS)+(angleT) = 360
90+110+90+x = 360
290+x = 360
290+x-290 = 360-290 ... subtract 290 from both sides
x = 70
<h3>angle T = 70</h3>
%change=100(final-initial)/initial
%change=100(25-40)/40=-37.5%
So Denise received a discount of 37.5% off the regular price.
Answer:
R = ![\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%26-2%5C%5C1%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
P - Q + R = I ( I is the identity matrix )
![\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%5C%5C3%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
- ![\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%262%5C%5C4%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R = ![\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
( subtract corresponding elements )
![\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2-%28-2%29%264-2%5C%5C3-4%265-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R =
![\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%5C%5C-1%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ R =
R = - =
Answer:
1
Step-by-step explanation:
first, solve in the parentheses then solve from there:
1 + 4 = 5
50 - 5^2 / 25
50 - (5 x 5 ) /25
50 - 25 / 25
25 / 25
1
