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Blababa [14]
3 years ago
9

1.)Can you map shape I onto shape II by a sequence of transformations? If so, give a sequence of transformations that maps shape

I onto shape II.
2.)Complete the sequence of transformations you found in part A, but in a different order. Does this also map shape I onto shape II? What does this mean?

3.)If you reflect any shape across the x-axis and then rotate it 90° clockwise about the origin, do you get the same result as if you reflect it across the y-axis and then rotate it 90° counterclockwise about the origin? What does this mean?

4.)If you reflect any shape across the x-axis and then rotate it 180° about the origin, do you get the same result that you would if you reflect it across the y-axis and then rotate it 180° about the origin? What does that mean?

5.)If you reflect any shape across the x-axis and then across the y-axis, do you get the same result that you would if you rotated it 180° about the origin? What does that mean?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

1.) Yes, it is possible to map shape I onto shape II using a sequence of transformations. One sequence involves reflecting shape I across the x-axis, rotating it 90° counterclockwise about the origin, and translating the shape 8 units up and 4 units left.

2.) Make a conjecture regarding a single rotation that will map ABC to A″B″C″. ... Specify a sequence of transformations that will carry a given figure onto ... of transformations that will carry a given figure onto another. Also. G-CO.A.2, G-CO. B.6 ... performing the transformations in Part B in a different order. 6.

No, if the sequence of transformations changes, shape 1 does not map shape 2. This means that the order of the transformations has an effect on the final shape.

3.) Yes, reflecting a shape across the x-axis and then rotating it 90° clockwise about the origin gives the same results as reflecting it across the y-axis followed by rotating it 90° counterclockwise about the origin. This means these two sequences of transformations are equivalent.

4.) No, the finished shapes would be in different quadrants

5.)Yes, for a shape, reflections across x- and y-axes give the same result as a 180° rotation about the origin. That means these two sequences of transformations are equivalent.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

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From trinomial expansion:

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open first two brackets to get a quadratic equation:

{(x - y)}^{3}  = ( {x}^{2}  - 2xy +  {y}^{2} )(x - y)

expand further:

{(x - y)}^{3}  =  {x}^{3}   - y {x}^{2}  - 2y {x}^{2}  + 2x {y}^{2}  + x {y}^{2}  -  {y}^{3}  \\  {(x - y)}^{3}  =  {x}^{3}  -  {y}^{3}  + 3x {y}^{2}  - 3y {x}^{2}  \\  {(x - y)}^{3}  =  {x}^{3}  -  {y}^{3}  + 3xy(y - x) \\  \\ { \boxed{( {x}^{3} -  {y}^{3} ) =  {(x - y)}^{3}   - 3xy(y - x)}}

take y to be 3, then substitute:

( {x}^{3}  - 3^3) =  {(x - 3)}^{3}  - 9x(3 - x)

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