All categories

2 years ago

2x +5 > -1 on the number line

Mathematics

1 answer:

Naya [18.7K]2 years ago

7 0

Answer:

Below

Step-by-step explanation:

2x + 5 > -1

Treat the equality sign (ex. < >) as the costumary equal sign (=).

2x + 5 + (-5) > -1 + (-5) ---- -5 will cancel out the 5 on the left

2x/2 > -6/2 ------ divide by 2 to single out the x

x > -3

Remember to draw an open dot. Draw an arrow from -3 to the extreme right.

You might be interested in

How do I add the fractions <br> 1/4 + 1/7 please help me

kiruha [24]

First, you have to find the LCD. The LCD of 4 and 7 is 28, so you rewrite the fraction:
7/28
4/28

Then you add them.

8 0

4 years ago

Read 2 more answers

10^9 is how many times the value of 10^8

slavikrds [6]

Answer:

10^9 is 10 × 10^8, since 10^9= 10×10×10×10×10×10×10×10×10

7 0

3 years ago

The diagram shows 5cm×5cm×5cm cube calculate the length of the diagonal ab

mario62 [17]

Answer:

AB = $5\sqrt{3}$ cm

Step-by-step explanation:

As we can see from the figure, BCDE is a square with each corner equal to 90°.

So that, BDE is a right triangle with corner BED equal to 90°

As BDE is a right triangle, according to Pythagoras theorem, we have:

$BD^{2} = BE^{2} +ED^{2} = 5^{2} + 5^{2} = 25 + 25 = 50$ cm

As the diagram s the cube, so that it can be seen that AD is perpendicular to the surface BCDE

=> AD is perpendicular to BD

=> ADB is the right triangle with corner ADB equal to 90°.

As ADB is the right triangle, ccording to Pythagoras theorem, we have:

$AB^{2} =AD^{2} + BD^{2} = 5^{2} +50 = 25 +50 = 75$ cm

=> $AB = \sqrt{75} = 5\sqrt{3}$ cm

Conclusion: AB = $5\sqrt{3}$ cm

4 0

3 years ago

ASAP

denis-greek [22]

<h2>Answer:</h2>

The constraint which represent a thriving population of penguins at the zoo is:

0 < x ≤ 10 and 0 < y ≤ 20.

<h2>Step-by-step explanation:</h2>

Let x = the number of female penguins and y = the number of male penguins.

Now, it is given that:

The group needs two times more males than females to thrive, and the zoo only has room for 10 female penguins.

This means that:

0 < x ≤ 10

( Because there are no room for more than 10 penguins )

Also,

y= 2x

Since,

x>0

This means that: 2x>0

i.e. y>0

and x ≤ 10

i.e. 2x ≤ 20

i.e. y ≤ 20

Hence, the constraints which represent a thriving population of penguins at the zoo is:

0 < x ≤ 10 and 0 < y ≤ 20.

4 0

3 years ago

Read 2 more answers

Alenkasestr [34]

We start with the expression at the left of the equation.

We can combine the terms as:

$\begin{gathered} \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}} \\ \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})} \end{gathered}$

We can now apply the distributive property for the both the numerator and denominator. We can see also that the denominator is the expansion of the difference of squares:

$\begin{gathered} \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2})^2-(\sqrt[]{2-\sqrt[]{3}}))^2} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})+(\sqrt[]{3}-2)\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{2^{}-(2-\sqrt[]{3})^{}} \\ \frac{\sqrt[]{2}\cdot(2+\sqrt[]{3})-\sqrt[]{2-\sqrt[]{3}}\cdot(2+\sqrt[]{3})+\sqrt[]{2}\cdot(\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}\cdot(\sqrt[]{3}-2)}{2-2+\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2+\sqrt[]{3}+\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}(-2-\sqrt[]{3}+\sqrt[]{3}-2)}{\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2\sqrt[]{3})+\sqrt[]{2-\sqrt[]{3}}(-4)}{\sqrt[]{3}} \\ 2\sqrt[]{2}-4\frac{\sqrt[]{2-\sqrt[]{3}}}{\sqrt[]{3}} \end{gathered}$

We then can continue rearranging this as:

7 0

1 year ago

2x +5 > -1 on the number line​

2x +5 > -1 on the number line