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sasho [114]
3 years ago
10

What is the answer to the question? T/34.56=15

Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer: The answer is T=518.4

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The mean of a set of credit scores is Mu = 690 and Sigma = 14. Which statement must be true about z694? z694 is within 1 standar
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Answer:

I believe it's B

Step-by-step explanation:

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Describe three transformation where the image and preimage have the same size and shape
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rotation, translation, and rotations

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8 trees increased by 175%
fredd [130]

Answer:

14

Step-by-step explanation:

8x175%= 14

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
2 years ago
Jackson has a gift card for $120 to use at a department store. he wants to purchase 2 shirts and 3 pairs of pants with his gift
mylen [45]
  • The domain of this relationship can be defined as,

0 ≤ x ≤ 60

  • The range of this relationship can be defined as,

0 ≤ y ≤ 40

Definition of Domain and Range

The set of  all the possible input values for which the provided function is defined is termed as the domain of that function.

The set of all the possible values that a given function can generate as an output is termed as the range of that function.

Forming the Relation

It is given that,

  • Jackson wants to purchase 2 shirts and 3 pairs of pants with his gift card
  • x represents the cost of the shirts and y represents the cost of the pants
  • The limit of the gift card = $120

Thus, the relation formed is given by,

2x + 3y \leq  120

Domain and Range of the Given Relation

We have,

2x + 3y \leq  120

⇒ 2x \leq 120

⇒ x\leq60

Thus, the domain is given by,

⇒ 0\leq x\leq 60

Similarly,

3y\leq 120

⇒ y\leq 40

Thus, the range is given by,

⇒ 0\leq y\leq 40

Learn more about domain and range here:

brainly.com/question/1632425

#SPJ4

7 0
2 years ago
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