B, for sure. Producers, Like grass and Flowers need water to make food. Consumers, like Cats, Snakes and Boars need water to drink so our internal systems will function properly.
Im not sure if decomposers need water, but if there is less water then more animals die and they get food. so, not sure about that one.
In prophase 1:
Chromosomes become visible, crossing-over occurs, the nucleolus disappears, the meiotic spindle forms, and the nuclear envelope disappears.
In metaphase 1:
The pairs of chromosomes (bivalents) become arranged on the metaphase plate and are attached to the now fully formed meiotic spindle. The centrioles are at opposite poles of the cell.
Answer:
0%
Explanation:
Round = Dominant
Wrinkled = recessive
Recessive = r
Dominant = R
homozygous dominant = RR
homozygous recessive = rr
Heterozygous= Rr
Since both seeds are homozygous recessive (rr)
In your punnet square, one lower case r will go on the top and the left side
r r
r
r
Something like that.
Go across your four boxes and you will end up with;
rr, rr
rr, rr
In order for it to be round, at least one box would need to have to be a heterozygous(Rr) or be a homozygous dominant.
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
