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DerKrebs [107]
3 years ago
14

Cora works as a plumber and earns $50 per house call, plus $18 for every hour of work. She billed a customer $104, but forgot ho

w long she worked. To solve for the number of hours, she subtracted 50 from 104 and then divided by 18.
Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

Cora worked 3 hours

Step-by-step explanation:

104 = 18x + 50 ( x = # of hours worked)

54 = 18x   ( subtracted 50 from both sides)

3 = x    ( divided both sides by 18)

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Find the rate of change given the following solutions: (6, 2) and (1, 12).
blagie [28]

Answer:

The rate of change is -2

Step-by-step explanation:

f(b)-f(a)     12-2              10

---------- = ------------  = -------- = -2

 b-a         1-6               -5

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3 years ago
PLEASE HELP!? i need to ro this for my exit ticket asap
rewona [7]

Answer:

It should be -3

Step-by-step explanation:

5 0
3 years ago
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SOMEONE HELP ASAP WHATS THE MISSING ANGLE
Lapatulllka [165]

Answer:

130

Step-by-step explanation:

? is an exterior angle of a triangle

An exterior angle is equal to the sum of the two opposite interior angles ( 35 and 95 in this case )

That being said the missing angle = 95 + 35

95 + 35 = 130

Hence, the answer is 130

7 0
3 years ago
Read 2 more answers
13. Write
Bingel [31]

First off, we factor out the expression:

\displaystyle \large{y = 2 {x}^{2}  - 12x + 16} \\  \displaystyle \large{y = 2 ( {x}^{2} - 6x + 8) }

In the bracket, separate 8 out of the expression.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\  \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

\displaystyle \large{ {(x - 3)}^{2}  =  {x}^{2}  - 6x + 9}

So we add +9 in x^2-6x.

\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9)  + 8]}

Convert the expression in the small bracket to perfect square.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8]}

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   + 8 - 9]} \\  \displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]}

Then we distribute 2 in.

\displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]} \\

\displaystyle \large{y = 2[  {(x - 3)}^{2}   - 1]} \\ \displaystyle \large{y = [2 \times  {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2}  - 2 }

Remember that negative multiply positive = negative.

Hence the vertex form is y = 2(x-3)^2-2 or first choice.

4 0
3 years ago
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