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Burka [1]
4 years ago
11

A 45 gram sample of a substance that's used to preserve fruit and vegetables has a k-value of 0.1088

Mathematics
2 answers:
Alekssandra [29.7K]4 years ago
8 0

Answer:

The substance's half-life is 6.4 days

Step-by-step explanation:

Recall that the half life of a substance is given by the time it takes for the substance to reduce to half of its initial amount. So in this case, where they give you the constant k (0.1088) in the exponential form:

N=N_0\,e^{-k\,*\,t}

we can replace k by its value, and solve for the time "t" needed for the initial amount N_0 to reduce to half of its value (N_0/2). Since the unknown resides in the exponent, to solve the equation we need to apply the natural logarithm:

N=N_0\,e^{-k\,*\,t}\\\frac{N_0}{2} =N_0\,e^{-0.1088\,*\,t}\\\frac{N_0}{2\,*N_0} =e^{-0.1088\,*\,t}\\\frac{1}{2} =e^{-0.1088\,*\,t}\\ln(\frac{1}{2} )=-0.1088\,t\\t=\frac{ln(\frac{1}{2} )}{-0.1088} \\t=6.37\,\,days

which rounded to the nearest tenth is: 6.4 days

mamaluj [8]4 years ago
6 0

Answer:

6.4

Step-by-step explanation:

I did it on the same site and got it correct

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1. Preparation of   the adjusting entries for

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Learn more here:brainly.com/question/21304366

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