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3 years ago

Please help me Domain: Range:

Mathematics

1 answer:

Soloha48 [4]3 years ago

3 0

Answer:

the domain is the X and the range is the Y

Step-by-step explanation:

hope this helps

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Paha777 [63]

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The pair of points is on the graph of an inverse variation. Find the missing value.

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Step-by-step explanation:

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Sketch the solid described by x 2 + y 2 ≤ z ≤ 1. Use the Divergence Theorem to evaluate the surface integral over the boundary o

kirill115 [55]

Looks like

$\vec F(x,y,z)=y\,\vec\imath+z\,\vec\jmath+xz\,\vec k$

The solid described by $x^2+y^2\le z\le 1$ is the interior of the region bounded by the paraboloid $z=x^2+y^2$ and the plane $z=1$ . Call this region $R$ .

By the divergence theorem,

$\displaystyle\iint_{\partial R}\vec F\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F\,\mathrm dV$

The divergence is

$\mathrm{div}\vec F(x,y,z)=(y)_x+(z)_y+(xz)_z=x$

so that the surface integral reduces to

$\displaystyle\iiint_Rx\,\mathrm dV$

or in cylindrical coordinates,

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1r^2\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{0}$

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3 years ago

What is the radius of a circle whose equation is (x + 5)2 + (y – 3)2 = 42? 2 units 4 units 8 units 16 units

KiRa [710]

Answer:

Option B.

Step-by-step explanation:

The given equation is

$(x+5)^2+(y-3)^2=4^2$ ...(1)

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$ ...(2)

where, (h,k) is center and r is radius of the circle.

On comparing (1) and (2) we get

$h=-5,k=3,r=4$

It means center of the circle is (-5,3) and radius of the circle is 4 units.

Therefore, the correct option is B.

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4 years ago

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viva [34]

Answer:

Its A i just took the test

Step-by-step explanation:

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3 years ago