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3 years ago

I have 7 classes impacting my grade equally.

Mathematics

1 answer:

Nitella [24]3 years ago

5 0

Answer:

like on each assignment a 90 or 100%

Step-by-step explanation:

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Factor the greatest common binomial factor from each polynomial

sladkih [1.3K]

Answer:
(5x-1)(6x^2+1)

Solution:
6x^2(5x-1)+5x-1
=30x^3-6x^2+5x-1
=(30x^3-6x^2) + (5x-1)
=6x^2(5x-1)+(5x-1)
=(5x-1)(6x^2+1)

HOPE THIS HELPS!

4 0

2 years ago

One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd

mart [117]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

Remember that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Find the slope of the first line

we have the points

(-3,-1) and (1,-9)

substitute in the formula

$m_1=\frac{-9+1}{1+3}$

$m_1=\frac{-8}{4}$

$m_1=-2$

Find the slope of the second line

we have the points

(1,4) and (5,6)

substitute in the formula

$m_2=\frac{6-4}{5-1}$

$m_2=\frac{2}{4}$

Simplify

$m_2=\frac{1}{2}$

Compare the slopes

$m_1=-2$

$m_2=\frac{1}{2}$

Find out the product

$m_1*m_2=(-2)(\frac{1}{2})=-1$

therefore

The lines are perpendicular

8 0

3 years ago

Read 2 more answers

a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r

galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ----> the area of the second square painting

D -----> the difference of the areas

we have

$A1=81x^{2}-90x-25$

$A2=25x^{2}+30x+9$

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

$D=(25x^{2}+30x+9)-(81x^{2}-90x-25)$

$D=(-56x^{2}+120x+34)$

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

$D=(81x^{2}-90x-25)-(25x^{2}+30x+9)$

$D=(56x^{2}-120x-34)$

4 0

4 years ago

A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha

vaieri [72.5K]

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

$P=x+y+z$ $2900=x+x+100+x+700$

we sum like terms

$2900=3x+800$

then we isolate the x

$3x=2900-800$ $3x=2100$ $x=\frac{2100}{3}=700$

therefore

x=700ft

y=700+100=800ft

z=700+700=1400ft

The lengths of the sides of the lote are 700 ,800, and 1400 ft,

8 0

1 year ago

Who wants to help me on question 41. I don't understand what it means when it says "label a net".

Novosadov [1.4K]

A net is basically a flattened out 3D solid. If you fold all the sides up, you would end up with the 3D model.

5 0

3 years ago

Read 2 more answers