Question

A capacitor is connected across an ac source. suppose the frequency of the source is doubled. what happens to the capacitive reactance of the capacitor?.

Answer 1

Answer:

Explanation:

The capacitive reactance of the capacitor is determined by $X_{C}=\frac{1}{\omega C}$

When $f'=2f \rightarrow \omega' =2\omega$

and $X_{C}'=\frac{1}{2}X_{C}$

(The capacitive reactance will be reduced into 1/2 times of the previous capacitive reactance)