One of the most important parts about creating great photographs starts with choosing what to photograph
1 answer:
You might be interested in
The rate of gain for the high reservoir would be 780 kj/s.
A. η = 35%
W =
W = 420 kj/s
Q2 = Q1-W
= 1200-420
= 780 kJ/S
<h3>What is the workdone by this engine?</h3>B. W = 420 kj/s
= 420x1000 w
= 4.2x10⁵W
The work done is 4.2x10⁵W
c. 780/308 - 1200/1000
= 2.532 - 1.2
= 1.332kj
The total enthropy gain is 1.332kj
D. Q1 = 1200
T1 = 1000
= 1200 - 369.6/1200
= 69.2 percent
change in s is zero for the reversible heat engine.
Read more on enthropy here: brainly.com/question/6364271
Answer:
a)
b)
c)
Explanation:
From the question we are told that:
Beaker Mass
Liquid Mass
Balance D:
Mass
Balance E:
Mass
Volume
a)
Generally the equation for Liquid's density is mathematically given by
b)
Generally the equation for D's Reading at A pulled is mathematically given by
m_d = mass of block - mass of liquid displaced
c)
Generally the equation for E's Reading at A pulled is mathematically given by