Hello from MrBillDoesMath!
Answer:
1/3
Discussion:
The problem looks complicated until you realize the term n^-4 appears in both the numerator and denominator. Hence their quotient is 1. That is,
n ^(-4) / ( 3 * n^(-4)) =
(n ^(-4) / n^(-4) ) * (1/3) =
1 * (1/3) =
1/3
Thank you,
MrB
Answer:
19,656
Step-by-step explanation:
Numbers used in locker = 3
Total numbers available = 28
Repetition is not allowed, so one number can be used only once. The order of number matters in the locker e.g. 123 password is not the same as 231. Since, the order of numbers matter, this is a problem of permutations. We need to find the number of different sequences formed with 28 numbers taken 3 at a time. This can be represented as 28P3
The formula for permutations is:

For the given case, we will have:

This means, 19,656 different 3 numbered sequences are possible for the locker.
Answer:
Total money get from soda cans = $259.2
Step-by-step explanation:
Given:
Number of soda cases = 18
Number of soda can in each case = 24
Price of each soda can = $0.60
Find:
Total money get from soda cans
Computation:
Total money get from soda cans = Number of soda cases x Number of soda can in each case x Price of each soda can
Total money get from soda cans = 18 x 24 x 0.60
Total money get from soda cans = $259.2
Step-by-step explanation:
6miles= 9656.064 metres