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galben [10]
2 years ago
10

What is X when 19,695 divided by X-15,605 = 100

Mathematics
1 answer:
Zepler [3.9K]2 years ago
3 0

Step-by-step explanation:

\frac{19695}{x - 15605}  = 100

19695 = 100(x - 15605)

19695 = 100x - 1560500

19695 + 1560500 = 100x

15801 95 = 100x

\frac{1580195}{100}  = x

x = 15801.95

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70. 180-120=60, and 180-60+50=70
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Which equation could represent "the area of a square as a function of a side"?
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Let side = x
area = x^2
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Which of the following ordered pairs is a solution of 2x-y=-9?
Ann [662]

Answer:

(4,-1)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
4 years ago
-x + 5y = 20 <br><br> 12y = 2x + 60
worty [1.4K]
-x+5y=20
5y=x+20
12y=2x+60
6y=x+40
x+20+y=x+40
-x from each side:
20+y=40
-20 from each side:
y=20

-x+5*20=20
-x+100=20
-100 from each side:
-x=-80
x=80

y=20
x=80

Hope this helps :)
6 0
3 years ago
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