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nirvana33 [79]
3 years ago
7

In the diagram, what is the value of x?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Step-by-step explanation:

There is no diagram, please update question.

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2. An empty ice cream cone has a height of 3.02 inches and a radius
ololo11 [35]

Answer:

Approximate volume of ice cream = 3.03 inches

Step-by-step explanation:

Given - An empty ice cream cone has a height of 3.02 inches and a radius

of 0.98 inches.

To find - What is the approximate volume of ice cream it will  hold within the cone  ?

Proof -

We know that,

Volume of the cone = \frac{1}{3}\pi r^{2}h

where

r is the radius of the cone

h is the height of the cone

Here,

Given that,

r = 0.98 inches

h = 3.02 inches

So,

Volume = \frac{1}{3}\pi r^{2}h

             = \frac{1}{3}(3.14) (0.98)^{2}(3.02)         ( Consider the value of \pi = 3.14)

             = 3.0373

∴ we get

Approximate volume of ice cream = 3.03 inches

So,

The correct option is - G. 3 in 3

8 0
3 years ago
Select all that apply.
Musya8 [376]

Answer:

The answer to this question is 2.137931034

Step-by-step explanation:

Just divide it by a calculator.

6 0
3 years ago
A chemist has 0.2 liters of an acid solution whose acid concentration is 65%. How many liters of pure water should be added to l
lorasvet [3.4K]

Answer:

0.06

Step-by-step explanation:

4 0
3 years ago
a product code consists of picking a two-digit number (including 00) and 3 not necessarily distinct letters. How many codes are
Brrunno [24]

Answer:

The codes are:

N,_,_,_

Where each _ represents a possible letter, out of 26.

And N is a number of two digits.

So in total we can think that we have 5 empty slots.

_,_,_,_,_

In the first slot we can put any digit between 0 and 9, so here we have 10 options.

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The total number of different combinations is equal to the product of the number of options for each slot.

C = 10*10*26*26*26 = 1,757,600

Now, if we want to have at least one nine, we can fix it in the first slot.

Then we have:

in the first slot we have only one option (the 9)

In the second slot we can put any digit between 0 and 9, so here we have 10 options.

In the third slot we can put any letter, so here we have 26 options (and exactly the same for the fourth and fifth slots)

The number of combinations is:

C = 1*10*26*26*26 = 175,760

But we also should consider the case where we fix the 9 in the second slot, so the actual number of combinations is twice the number above.

C = 2*175,760 = 351,520

The probability that the code does not contain the number 9.

Now in the first slot we have only 9 options, all the whole numbers between 0 and 8.

The same for the second slot, 9 options.

For the third, fourth and fifth slot is the same as before.

The total number of combinations is:

C = 9*9*26*26*26 = 1,423,656

4 0
3 years ago
Will give brainliest for right answers please help
Scrat [10]
1. A
2. B
3. B
4. A
5. C
6 0
3 years ago
Read 2 more answers
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