Answer:
3 times
Explanation:
When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model
![T(n)=T_0(1+r)^n](https://tex.z-dn.net/?f=T%28n%29%3DT_0%281%2Br%29%5En)
Where:
Initial thickness,
= 2mm
Growth factor, r =8%=0.08
We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.
i.e When ![T(n)\geq 2.5$ mm](https://tex.z-dn.net/?f=T%28n%29%5Cgeq%202.5%24%20mm)
![2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9](https://tex.z-dn.net/?f=2%281%2B0.08%29%5En%5Cgeq%202.5%5C%5C2%281.08%29%5En%5Cgeq%202.5%5C%5C%24Divide%20both%20sides%20by%202%24%5C%5C%5Cdfrac%7B2%281.08%29%5En%7D%7B2%7D%5Cgeq%20%5Cdfrac%7B2.5%7D%7B2%7D%5C%5C%5C%5C1.08%5En%5Cgeq%201.25%5C%5C%5C%5C%24Change%20to%20logarithm%20form%5C%5Cn%20%5Cgeq%20%5Clog_%7B1.08%7D1.25%5C%5C%5C%5Cn%5Cgeq%20%5Cdfrac%7B%5Clog%201.25%7D%7B%5Clog%201.08%7D%20%5C%5C%5C%5Cn%5Cgeq%202.9)
Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.
Yes, they can.
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Answer:Arturo usually feel comfortable in the restaurant. But today, in the kitchen, he working for martin, who refuse to treat him specially.
Explanation: