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3 years ago

ANSWER THIS PLEASE !!!!!!

Mathematics

1 answer:

Korolek [52]3 years ago

5 0

Answer:

Step-by-step explanation:

Becuase 68 is closer to c than b

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Which of the following is equivalent to the

Mandarinka [93]

Wheres the expression?

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3 years ago

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The string of a kite is 100 meters long and it makes an angle of 60° with the ground. What is the height of the kite?

Naddika [18.5K]

Answer:

50√3 ≈ 86.6 m

Step-by-step explanation:

The geometry can be modeled by a right triangle with the height of the kite being the leg opposite the 60° angle. The hypotenuse has the given length of 100 m.

The mnemonic SOH CAH TOA reminds you that the relation between angles and the sides of interest here is ...

Sin = Opposite/Hypotenuse

sin(60°) = (kite height)/(100 m)

kite height = (100 m)·sin(60°) = (100 m)(√3)/2

kite height = 50√3 m ≈ 86.6 m

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3 years ago

Determine the equation of the circle graphed below.

myrzilka [38]

Answer:

$= > {x}^{2} + {y}^{2} + 6x - 14y + 49 = 0$

Step-by-step explanation:

From the graph we can see that

Diameter = 6 units

=> Radius = 3 units and centre is at (-3,7)

=> Equation is Circle with centre (-3,7) and radius of 3 units will be

$= > {(x + 3)}^{2} + {(y - 7)}^{2} = {3}^{2}$

$= > ( {x}^{2} + 6x + 9) + ( {y}^{2} - 14y + 49) = 9$

$= > {x}^{2} + {y}^{2} + 6x - 14y + 49 = 0$

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3 years ago

Analyze the graph of a cannonball launched from the ground with an initial velocity of 144 feet per second. The cannonball reach

MrRissso [65]

We can find that the formula is:
$h(t)=-16t^2 + 144t$

We are told that the cannonball reaches its maximum height at t = 4.5 seconds. To find the maximum height, let's just plug this into the formula:
$h(4.5) = -16(4.5)^2 + 144(4.5) = 324$

The height is 324 feet. We're done!

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3 years ago

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Using the equation y=kx and the table below, find the constant of proportionality (k).

elena-s [515]

Answer:

k = 9/4

Step-by-step explanation:

To find k, use the equation

y = kx

Pick a point

72 = k *32

Divide each side by 32

72/32 = k

9/4 = k

4 0

3 years ago

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