So the mean without 894 would be 52.57
with the 894, the mean would be 157.75
idk what your options are, but there ya go
![\begin{gathered} b)True \\ c)3528cm³ \\ d)_0.0016kg \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%29True%20%5C%5C%20c%293528cm%C2%B3%20%5C%5C%20d%29_0.0016kg%20%5Cend%7Bgathered%7D)
b) By capacity, the problem asks the volume. So let's find the volume of that small cylinder
![\begin{gathered} V=\pi r^2h \\ 808.5=\frac{22}{7}\cdot(\frac{7}{2})²\cdot21 \\ 808.5=\frac{22}{7}\cdot\frac{49}{4}\cdot\:21 \\ 808.5=\frac{1617}{2} \\ 808.5=808.5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cpi%20r%5E2h%20%5C%5C%20808.5%3D%5Cfrac%7B22%7D%7B7%7D%5Ccdot%28%5Cfrac%7B7%7D%7B2%7D%29%C2%B2%5Ccdot21%20%5C%5C%20808.5%3D%5Cfrac%7B22%7D%7B7%7D%5Ccdot%5Cfrac%7B49%7D%7B4%7D%5Ccdot%5C%3A21%20%5C%5C%20808.5%3D%5Cfrac%7B1617%7D%7B2%7D%20%5C%5C%20808.5%3D808.5%20%5Cend%7Bgathered%7D)
So by plugging into the formula the given data we can tell that the capacity of that cylinder is indeed 808.5cm³
c) Note that now, the point is to find the Volume of that cuboid (rectangular prism), which we can find by doing the following formula:
![\begin{gathered} V=A_b\cdot h \\ V=(14\cdot12)\cdot21 \\ V=3528cm³ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3DA_b%5Ccdot%20h%20%5C%5C%20V%3D%2814%5Ccdot12%29%5Ccdot21%20%5C%5C%20V%3D3528cm%C2%B3%20%5Cend%7Bgathered%7D)
d) And finally, the density is given by the following ratio:
Answer:
18/24 + 4/24 = 22/24 (22/24 simplified is 11/12)
Hi there! Hopefully this helps!
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<em>Answer to the first equation:</em><u><em> 3.</em></u>
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<em>Answer to the second equation: </em><u><em>7</em></u>
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<em>Answer to the third equation: </em><u><em>-2.</em></u>
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<em>Answer to the fourth equation: </em><u><em>-3</em></u>
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