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katrin2010 [14]
3 years ago
11

Please help me with this too ,​

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

Step-by-step explanation:

\sf a^{m}*a^{n} =a^{m +n}\\\\a^{\frac{1}{n}}=\sqrt[n]{a}

\sf a^{-n}=\dfrac{1}{a^{n}}\\\\\dfrac{a^{n}}{a^{m}}=a^{n-m}\\\\\\a^{0}=1

\sf (a^{n})^{m} = a^{n*m}\\\\(a^{n}*b^{m})^{p}=a^{np}b^{mp}\\\\(ab)^{n}=a^{n}b^{n}

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How do you do inequalities
Alexandra [31]

Answer:

Summary Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own. But these things will change direction of the inequality: Multiplying or dividing both sides by a negative number. Swapping left and right hand sides

Step-by-step explanation:

6 0
2 years ago
A graphing calculator displays 1.89•10^12 as 1.89e 12. How do you think it would display 1.89•10^-12? What does the E stand for?
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3 years ago
If a square has an area of 196 square feet. what is the perimeter of the sandbox?
IRINA_888 [86]
The area of a rectangular shape is found my multiplying the base x height. Since squares have the same measure all the way around the base must be equal to height so b x h for a square is equal to (b x b)=b^2 or (h x h)^2 they are the same to using b for base we have b^2=196 so sqrt(196) = each side is 14sqft. To find the perimeter we just add all the sides to get (14+14+14+14) or (14*4)= 56sqft.
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3 years ago
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liberstina [14]

Answer:

16%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The length of the base of a triangle is twice its height. if the area of the triangle is 225 square kilometers, find the height
Anon25 [30]
Let
x----------> length of the base
y----------> height

we know that
[the area of triangle]=[length of the base]*[height]/2
x=2y
A=225 km²
225=x*y/2---------> 225=(2y)*y/2-----> y²=225--------> y=15 km
x=2y--------> x=2*15------> x=30 km

the answer is
the height is 15 km

3 0
4 years ago
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