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3 years ago

In how many ways can the word "calculus" be arrange so that two L's do not come together?

1 answer:

6 0

Count the total number of permutations of the word "calculus": there are 8 letters, hence 8! = 40,320 total permutations.

Count the number of permutations in which the two L's occur next to each other. Effectively we're now talking about words consisting of 7 letters, of which there are 7! = 5,040.

It follows that there are

8! - 7! = 35,280

words in which two L's do not appear next to each other.

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In how many ways can the word "calculus" be arrange so that two L's do not come together?​

In how many ways can the word "calculus" be arrange so that two L's do not come together?