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Grace [21]
2 years ago
5

The water level in a pool is currently at 1/2 of an inch. Every hour, the water level increases 4.75 inches. How many hours will

it take the water level to reach 33.75 inches?
Mathematics
1 answer:
____ [38]2 years ago
6 0

Answer:

7.1 hours

Step-by-step explanation:

Given data

Let the number of hours taken to fill the pool be x

the current quantity is 1/2 the capacity of the pool

we are given that the rate of flow = 4.75 in per hour

let the total amount of water after x hours be y, the expression for the quantity of water is given as

y= 0.5+4.75x

if y= 33.75 in, let us find x

33.75= 0.5+4.75x\\\\33.75-0.5= 4.75x\\\\33.25= 4.75x\\\\

divide both sides by 4.75

x= 33.75/4.75\\\\x= 7.10

Hence, it will take 7.1 hours

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The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
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Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

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b)

i) SD = 0.65

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= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

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= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

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c)

i) SD = 0.8

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z = (Xbar - mu) / (SD/sqrt(n))

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= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

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2 years ago
Which of the following transformations are used when transforming the graph of the parent function...
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1. 1st transformation is translation the parent function y=\log_5x 6 units to the right to get the function y=\log_5(x-6).

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3. 3rd transformation is vertical stretch of the function y=-\log_5(x-6) by a factor of 2 to get the function y=-2\log_5(x-6).

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Answer:

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