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k0ka [10]
3 years ago
14

833/90 as a mixed number

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

833/90 as a mixed number is 9 and 23/90.

Step-by-step explanation:

How many times does 90 go in to 833? 9 times.

Then take the remaining so you can’t really simplify the fraction so it stays 23/90.

So your final answer is 9 and 23/90.

Brainliest pls!!!

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Ten less than three times the sum of x and seven is twenty-six.
Orlov [11]

Answer:

<u>x = 12</u>

Step-by-step explanation:

10 - 3 ( x + 7 ) = 26

<em>First Step: Distribute</em>

- 3 to ( x + 7 )

=  10 - 3 x - 21 = 26

<em>Second Step: Combine like terms</em>

10 - 21

=  - 11 - 3 x = 26

<em>Third Step: Add from both sides</em>

26 + 11

=  - 3 x = 37

<em>Fourth Step: Divide from both sides</em>

37 / - 3

<u>x = 12</u>

6 0
3 years ago
Is it an identity? and how?
frutty [35]
Yes, it's an identity because remember sin 6x would be (3x + 3x)= which would make it 2 sin 3x....concluding the equation should be an identity. :)


Hoped this helped :)
6 0
3 years ago
Help !! 10 points!! :)
Zolol [24]

Answer:

line f

Step-by-step explanation:

6 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
I need help!! Can someone help me?¿
wolverine [178]
Sorry don't know explane the question
7 0
4 years ago
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