V(t) = 2t^2 - 3t - 3
for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3
at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2
Answer:
However, we need to know that segment AB is congruent to segment CD, in order to use SAS.
Hope it helps!
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You have:
Sinα=opposite/hypotenuse
α=62°
opposite=x
hypotenuse=15 ft
2. When you substitute the values into Sinα=opposite/hypotenuse, you obtain:
Sinα=opposite/hypotenuse
Sin(62°)=x/15
3. You must clear "x", as below:
x=(15)(Sin(62°))
x=13.24 ft
The answer is. 13.24 ft
If my memory serves me well, the only wtatement which is true is the last one: <span>D) All linear equation and all quadratic equations are polynomial equations.</span>
Answer:
A
Step-by-step explanation:
The correct option is (A).
