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Jlenok [28]
3 years ago
6

Worth 33 points!

Mathematics
2 answers:
eduard3 years ago
6 0

Answer:

(-3,1)

Step-by-step explanation:

As their are two lines so these are simultaneous linear equations

  • The solution is the point or coordinate at which they intersect with each other

Hence this is (-3,1)

Ivan3 years ago
4 0
<h3>Answer:</h3>
  • (-3, 1)    
<h3>Step-by-step explanation:</h3>

Note: The solution of a graph is the intersection of 2 lines.

<u>Plotting the solution on the graph:</u>

To plot the solution on the graph,

  1. Look for the intersection point of the two lines.
  2. Make a dot on the graph to represent the solution.

<u>Identifying a solution on the graph:</u>

To identify the solution, you willl need to determine it's coordinates.

     1. Determine the x and y coordinate by drawing a line going                                 downwards and rightwards. Keep in mind that the                                               intersection of the lines on the x and y axis are the x and y                               coordinates repectively.

  • (It is suggested that the line should be drawn with a ruler).

    2. The x and y coordinate obtained should be put in (x,y) form.

<u>Determining the solution on the graph:</u>

⇒ Intersection point: (x, y) = (x = -3; y = 1) = (-3, 1)                [Refer to image]

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so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3

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I think this is the answer because it's asking for an expression which this would be one.

5 0
3 years ago
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