0.6=k
This is your answer because the equation is for direct variation is y=kx
You substitute the numbers
Answer:
The numbers are 20 and 140
Step-by-step explanation:
<u><em>The question in English is</em></u>
Find 2 numbers knowing that the second number is 7 times greater than the first, and the sum between the double of the first number and the triple of the second is 460
Define the variables
Let
x ----> the first number
y ----> the second number
we know that
-----> equation A
----> equation B
Solve the system of equations by substitution
Substitute equation A in equation B
solve for x
<em>Find the value of y</em>
----> 
The numbers are 20 and 140
The Answer would be -6(3x-5).
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3
1 - 9
2 -28
3 54
4 -100
5 -60
6 0
7 49
8 -135
9 -96
10 300
11 0
12 192
