1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
satela [25.4K]
2 years ago
8

This property of matter describes a substance's ability to be stretched thin?

Physics
1 answer:
Lyrx [107]2 years ago
8 0

Answer:

Ductility

Explanation:

is the physical property of a material associated with the ability to be hammered thin or stretched into wire without breaking. A ductile substance can be drawn into a wire.

You might be interested in
Can lamp that works on a 2.5 v work on a 1.12 v ?​
12345 [234]

Answer:

Explanation:

Thinking about the logics it can but it may be dim because 1.12 is lower than 2,5v so this will mean u lamp may not work or may work very dimely due to the low voltage it is receiving.

5 0
3 years ago
MIDDLE SCHOOL: What are the three types of energy used when cleaning? (Please write them in order of occurrence)
tankabanditka [31]

Answer:

Chemical, mechanical, thermal i guess

7 0
3 years ago
A) 1.2-kg ball is hanging from the end of a rope. The rope hangs at an angle 20° from the vertical when a 19 m/s horizontal wind
Marat540 [252]

Answer:

Part a)

F_v = 4.28 N

Part B)

L = 1.02 m

Part C)

v = 1.25 m/s

Explanation:

Part A)

As we know that ball is hanging from the top and its angle with the vertical is 20 degree

so we will have

Tcos\theta = mg

T sin\theta = F_v

\frac{F_v}{mg} = tan\theta

F_v = mg tan\theta

F_v = 1.2\times 9.81 (tan20)

F_v = 4.28 N

Part B)

Here we can use energy theorem to find the distance that it will move

-\mu mg cos\theta L + mg sin\theta L = -\frac{1}{2}mv^2

(-(0.37)m(9.81) cos15 + m(9.81) sin15)L = - \frac{1}{2}m(1.4)^2

(-3.5 + 2.54)L = - 0.98

L = 1.02 m

Part C)

At terminal speed condition we know that

F_v = mg

bv^2 = mg

2.5 v^2 = 3.9

v = 1.25 m/s

7 0
3 years ago
Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi
stira [4]

Answer:D

Explanation:according to the law of conservation of energy/momentum, when two bodies collides, their total momentum and energy before and after collision are equal. Given that the two bodies move with the same velocities after collision, means that the law has not been violated since momentum = mass x velocity (where mass is constant)

4 0
4 years ago
a horse began running due east and covered 25km in 4.0 hours what is the average velocity of the horse
Komok [63]

25km / 4hr = <em>6.25 km/hr east</em>

6 0
3 years ago
Read 2 more answers
Other questions:
  • If light moves from left to right along the x-axis, then the electric field line vibrates along what?? :(
    14·1 answer
  • The moon's orbit around the Earth will advance in one day:<br><br> 1°<br> 13°<br> 27°<br> 29°
    9·2 answers
  • At the type of plate boundary shown in the image above, two plates are colliding. Which type of plate boundary is shown in this
    6·2 answers
  • In midair in the international space station a 1 kg chunk of putty moving at 1 m/s collides with and sticks to a 5 kg chunk of p
    14·1 answer
  • An object's (mass or weight) will remain constant throughout the universe, but its (mass or weight) can change from planet to pl
    10·2 answers
  • An Alaskan rescue plane traveling 37 m/s drops a package of emergency rations from a height of 134 m to a stranded party of expl
    11·1 answer
  • Which is a chemical reaction that uses up energy?
    8·2 answers
  • In a nuclear fusion reaction two 2H atoms are combined to produce one 4He.
    6·1 answer
  • David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady
    14·2 answers
  • Leverrier predicted that an invisible planet was pulling the planet Uranus off its predicted course around the sun. Likewise, hu
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!