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FromTheMoon [43]
3 years ago
13

Write a collision scenario here. If you choose your own collision, you can have neither, one, or both of the objects break. Be s

ure to describe which object (if any) breaks.
Physics
1 answer:
OleMash [197]3 years ago
5 0

Answer:

My scenario would be A Car vs. a guard rail on a road.  You have a car that is coming down a Highway at a speed of 43 Mph Miles per hour (69.2018 Kmh)

And it hits a steel guardrail and the car smashes in at the front and the guardrail is only bent while the car has the bumper and the hood along with the headlights and windshield along with the passenger side window break.

Explanation:

This is caused by so much force reacting from one object to another but also depends on molecular density.

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What will happen to the ball in example C if there is no friction?
Sloan [31]

Answer:

A) The ball will roll forever in a straight path.

8 0
3 years ago
1. To get to school, a girl walks 1 km North in 15 minutes. She
yulyashka [42]

Answer:

Average velocity of the girl is 1.25 m/s.

Explanation:

3 0
3 years ago
Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr
nordsb [41]

Answer:

W=3456 N

Explanation:

Force 1 F_1=3456

Force 2 F_2=2333N

Acceleration at stage 2 a_2=0.39

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

W=3456 N

5 0
3 years ago
Si tomamos como referencia el recipiente uno y se aplican 5 gramos de tinta y el agua se moviera a una velocidad de 10m/s cual s
tigry1 [53]

Answer:

Kinetic energy = 0.25 J

Explanation:

The question is "If we take container one as a reference and apply 5 grams of ink and the water moves at a speed of 10m / s, what would the kinetic energy of the solution be?"

We have,

Mass of ink, m = 5 grams = 0.005 kg

Speed of water, v = 10 m/s

We need to find the kinetic energy of the solution of water and ink. Kinetic energy is associated with the motion of an object. Its formula is given by :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.005\times (10)^2\\\\K=0.25\ J

So, the kinetic energy of the solution is 0.25 Joules.

5 0
4 years ago
A bag is dropped from a balloon that is 50m above the ground and rising at 15m/s. calculate
ANTONII [103]

Answer:

See the answers below

Explanation:

We can solve this problem using the principle of energy conservation. That is, the energy is conserved before and after dropping the bag.

For this case we have mechanical energy, which is the sum of the kinetic and potential energies.

E_{1}=E_{2}

where:

E_{1}=E_{k}+E_{p}\\E_{2}=E_{p}

Ek = kinetic energy [J] (units of Joules)

Ep = potential energy [J]

In the final Energy (2), there is only potential energy. since when the balloon reaches the maximum height its velocity is zero, that is, there is no kinetic energy.

A)

m*g*h+\frac{1}{2}*m*v^{2} =m*g*h_{1} \\9.81*50+0.5*(15)^{2}=9.81*h_{1}\\h_{1} = 61.46 [m]

B)

With the value calculated above we can find the acceleration of the balloon.

The distance traveled is the difference between the maximum height and 50 meters.

x = 61.46-50\\x = 11.46[m]

With the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}+2*a*x

0 = 15^{2} +2*a*11.46\\a = - 9.816 [m/s^{2} ]

The negative sign indicates that the acceleration acts downward. That is, in the opposite direction to the movement.

We can use the following equation of kinematics to find the final velocity after 4 seconds.

v_{f}=v_{o}-a*t\\v_{f}=15-9.816*(4)\\v_{f}=-24.24 [m/s]

Now the distance:

v_{f}^{2} =v_{o}^{2}-2*a*x\\(24.24)^{2} =(15)^{2} -2*9.81*x\\x = 18.48 [m]\\x_{f}=50+18.48 = 68.48 [m]

c) Using the following equation of kinematics.

v_{f}=v_{o}-a*t\\0 = 15-9.81*t\\15=9.81*t\\t = 1.52 [s]

4 0
3 years ago
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