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3 years ago

Some ethical characteristics that you will want to aspire to include honesty, compassion, attentiveness, and:

Advanced Placement (AP)

1 answer:

Verdich [7]3 years ago

5 0

Answer:

punctuality

Explanation:

Honesty, compassion, attentiveness, and punctuality are the 4 moral ethics

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A 2 kg object moves along the x axis. The only force on it depends on time and equals (4N/s^2)t^2 + 4N. if the object is at rest

Vitek1552 [10]

Answer:

The change in momentum equals the area under the graph (the impulse). That area is 4N * 3s - 2N * 2s = 8 N s. Therefore . m delta(v) = 8 kg m/s. 1.2 kg * ( v(6) - v(0) ) = 8 kg m/s

Explanation:

A)An object cannot remain at rest unless the net force acting on it is zero. B) If a block is moving to the left with constant velocity the net force applied to the block is zero. C) A block of mass 2 kg is acted upon by two forces: 3N (directed to the left) and 4N (directed to the right).

7 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago

The equation 3x + 2 = 29 is modeled below.

raketka [301]

3x+2=29

3x=27

x=9

Hope this helps

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2 years ago

Which of the following is a suggested practice to engage families in two-way communication?

balandron [24]

Answer:

D) Take-home backpacks.

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3 years ago

A local coffee shop gives out a free cup of coffee for every 10 cups of coffee you buy. The donut place across the street gives

AnnyKZ [126]

E - Continuous reinforcement. None of these are punishments and cassical conditioning involves assimilating two stimuli

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3 years ago