Answer:
Option 4
Step-by-step explanation:
-½ means it's -0.5, and then -0.4 then -3/10 = -0.3 and then -0.23, therefore it goes -½, -0.4, -3/10, then -0.23
Answer:
The given sums 11+17+23+29+35+41 can be written as in sigma notation is 
Therefore 11+17+23+29+35+41=
Step-by-step explanation:
Given series is 11+17+23+29+35+41
To find the given sum expressed in sigma notation :
11+17+23+29+35+41 can be written as the given sums in sigma notation is 
That is
11+17+23+29+35+41=
Now expand the sums and to verify that whether the summation is true or not :



Therefore 11+17+23+29+35+41=
Show that there do not exist scalars c1, c2, and c3 such that c1(1, 0, 1, 0) + c2(1, 0, -2, 1) + c3(2, 0, 1, 2) = (1, -2, 2, 3)
Aloiza [94]
Write the system in augmented-matrix form:

![\iff\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\1&-2&1&2\\0&1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Ciff%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%262%261%5C%5C0%260%260%26-2%5C%5C1%26-2%261%262%5C%5C0%261%262%263%5Cend%7Barray%7D%5Cright%5D)
Row reduce this matrix:
![\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&-3&-1&1\\0&1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%262%261%5C%5C0%260%260%26-2%5C%5C0%26-3%26-1%261%5C%5C0%261%262%263%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&5&10\\0&1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%262%261%5C%5C0%260%260%26-2%5C%5C0%260%265%2610%5C%5C0%261%262%263%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&1&2\\0&1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%262%261%5C%5C0%260%260%26-2%5C%5C0%260%261%262%5C%5C0%261%262%263%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&1&2\\0&1&0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%262%261%5C%5C0%260%260%26-2%5C%5C0%260%261%262%5C%5C0%261%260%26-1%5Cend%7Barray%7D%5Cright%5D)
- Add -2(row 3) and -1(row 4) to row 1:
![\left[\begin{array}{ccc|c}1&0&0&-2\\0&0&0&-2\\0&0&1&2\\0&1&0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%26-2%5C%5C0%260%260%26-2%5C%5C0%260%261%262%5C%5C0%261%260%26-1%5Cend%7Barray%7D%5Cright%5D)
This matrix tells us that
,
, and
, but clearly
, so there is no solution.
Answer:
(6, 5)
Step-by-step explanation:
add x's divide by 2 add y's divide by two
Answer:
isosceles but not equilateral
<h2>stay safe healthy and happy.</h2>