Can someone plz help hereI got confused
1 answer:
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<u>Given</u><u> info</u><u>:</u><u>-</u> In triangle (∆)ABC , in which ∠A = 2x, ∠B = x+15° and ∠C = 2x + 10°. Then find the value of x , also find the measure of each angles of a triangle.
<u>Explanation</u><u>:</u><u>-</u>
Let the angles be 2x, x+15 and 2x+10 respectively.
∵ Sum of the three angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180° [Sum of ∠s of a ∆=180°]
→2x + x+15 + 2x+10 = 180°
→ 2x + x + 2x + 15 + 10 = 180°
→ 3x + 2x + 15 + 10 = 180°
→ 5x + 15 + 10 = 180°
→ 5x + 25 = 180°
→ 5x = 180°-25
→ 5x = 155°
→ x = 155°÷5 = 155/5 = 31.
Now, finding the measure of each angles of a ∆ABC by putting the original value of “x”.
∴ ∠A = 2x = 2(31) = 62°
∠B = x+15 = 31 + 15 = 46°
∠C = 2x + 10 = 2(31) + 10 = 62 + 10 = 72°.
Step-by-step explanation:
Hey there!!!!
We generally sum up all the angles to get 360° as per given in our question.
Here, in your question, we have values as,
x, 2x, 100°, 110°.
(We have 360° as the sum quadrilateral).
So, x° + 2x° + 100°+110° = 360°
3x°+210°= 360°
3x° = 360° - 210°
or, 3x° = 150°
Therefore the measure of 2x is (2×50)°=100°.
<em><u>Hope</u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>