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2 years ago

Identify the numbers that are located to the right of -4 1/3 on a horizontal number line

Mathematics

1 answer:

QveST [7]2 years ago

7 0

Answer:

- 1/2

5 1/2

-3 2/3

-1 2/3

2/3

-4

Step-by-step explanation:

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The measure of the exterior angle is ________

masha68 [24]

I’ll try please wait

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3 years ago

Read 2 more answers

(question is on picture linked)

nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

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3 years ago

One fifth of a number plus five times that number is equal to seven times the number less 18. find the number.

Schach [20]

OK. First we have to figure out names for all the numbers you mentioned.

The mysterious number . . . . . call it Q
One fifth of the number . . . . . 0.2 Q
Five times the number . . . . . . 5 Q
Seven times the number . . . . 7 Q

(One fifth plus five times the number) . . . 5.2 Q
(Seven times the number less 18) . . . . . . 7 Q - 18

You said that these last two things are equal,

so I can write . . . . . . . . . . . . . . . . . . 7 Q - 18 = 5.2 Q

Now, subtract 7Q from each side . . . -18 = -1.8 Q

Divide each side by -1.8 . . . . . . . . . . 10 = Q

6 0

3 years ago

Find the greatest common factor of these two expressions.

Sedbober [7]

Answer:

Step-by-step explanation:

i dont know sorry

3 0

3 years ago

A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair a

vesna_86 [32]

$Chair=x$

$Table=y$

$Desk=z$

$\begin{Bmatrix}x+y&=&40\\y+z&=&83\\x+z&=&77\end{matrix}$

keep the first row as normal, then in the other ones, we can isolate Y and X

$\begin{Bmatrix}x+y&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

now we can replace at first row...

$\begin{Bmatrix}(77-z)+(83-z)&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}160-2z&=&40\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&40-160\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}-2z&=&-120\\y&=&83-z\\x&=&77-z\end{matrix}$

$\begin{Bmatrix}z&=&60\\y&=&83-z\\x&=&77-z\end{matrix}$

now we can replace the Z to discovery the other value

$\begin{Bmatrix}z&=&60\\y&=&83-60\\x&=&77-60\end{matrix}$

$\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\\Table&=&23\\Desk&=&60\end{matrix}}}}$

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4 years ago