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Finger [1]
3 years ago
12

6.5 + (−2) + 10.5 I could probably do this but its kind of hard to understand. Explain?

Mathematics
1 answer:
elena-s [515]3 years ago
6 0
Hello! Let's work this problem from left to right to make things a bit easier ;)

6.5+(-2) is the same as 6.5-2, since adding a negative is the same as subtracting a positive. 6.5-2=4.5

Now, we have to add 10.5 to 4.5, which gives us the grand total of 15. I hope this helped! Let me know if you need anything else!
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11. Find the coordinates of A' and B'if A (3,5) and B (-7, 3) undergo
NISA [10]
<h2>Answer:(-3,-5),(7,-3)</h2>

Step-by-step explanation:

If a point (x,y) gets reflected about origin,the new point formed after reflection is (-x,-y).

Given that A=(3,5),

So,A'=(-3,-5)

Given that B=(-7,3),

So,B'=(-(-7),-3)=(7,-3)

4 0
3 years ago
How do I solve this 6-3=□-2
Sonja [21]
Well, first what is 6-3=3 so now whats 3-2? 3-2=1 
6-3=3-2
8 0
3 years ago
A 1400 kg car moving +13.7 m/s makes an elastic collision with a 3200 kg truck, initially at rest. What is the velocity of the c
Kamila [148]

Answer:

The velocity of the car after the collision is -5.36 m/s

Step-by-step explanation:

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

let the following:

m₁ = mass of the car = 1400 kg

m₂ = mass of the truck = 3200 kg

u₁ = velocity of the car before collision = 13.7 m/s

u₂ = velocity of the truck before collision = 0 m/s

v₁ = velocity of the car after collision

v₂ = velocity of the truck after collision

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

   =  [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)

   = - 5.36 m/s

So, <u>the velocity of the car after the collision is -5.36 m/s</u>

7 0
3 years ago
What is the answer for the diagram?
Westkost [7]

Answer:

1340-

Step-by-step explanation:

5 0
3 years ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
nikklg [1K]

Step-by-step explanation:

<u>Step 1:  Solve using the first point</u>

<em>(2, 28)</em>

28 = a(2)^3 + b(2)^2 + c(2) + d

28 = 8a + 4b + 2c + d

<u>Step 2:  Solve using the second point</u>

<em>(-1, -5)</em>

-5 = a(-1)^3 + b(-1)^2 + c(-1) + d

-5 = -a + b - c + d

<u>Step 3:  Solve using the third point</u>

<em>(4, 220)</em>

220 = a(4)^3 + b(4)^2 + c(4) + d

220 = 64a + 16b + 4c + d

<u>Step 4:  Solve using the fourth point</u>

<em>(-2, -20)</em>

-20 = a(-2)^3 + b(-2)^2 + c(-2) + d

-20 = -8a + 4b - 2c + d

<u>Step 5:  Combine the first and fourth equations</u>

<u />28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d

8 = 8b + 2d

8 - 8b = 8b - 8b + 2d

(8 -8b)/2 = 2d/2

4 - 4b = d

<u>Step 6:  Solve for c in the second equation</u>

-5 + 5 = -a + b - c + d + 5

0 + c = -a + b - c + c + d + 5

c = -a + b + d + 5

<u>Step 7:  Substitute d with the stuff we got in step 5</u>

c = -a + b + (4 - 4b) + 5

c = -a + b + 4 - 4b + 5

c = -a - 3b + 9

<u>Step 8:  Substitute d and c into the first equation</u>

<u />28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)

28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b

28 - 22 = 6a - 6b + 22 - 22

6 / 6 = (6a - 6b) / 6

1 + b = a - b + b

1 + b = a

<u>Step 9:  Substitute a, b, and c into the third equation</u>

220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)

220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b

220 - 100 = 60b + 100 - 100

120 / 60 = 60b / 60

2 = b

<u>Step 10:  Find a using b = 2</u>

a = b + 1

a = (2) + 1

a = 3

<u>Step 11:  Find c using a = 3 and b = 2</u>

c = -a - 3b + 9

c = -(3) - 3(2) + 9

c = -3 - 6 + 9

c = 0

<u>Step 12:  Find d using b = 2</u>

d = 4 - 4b

d = 4 - 4(2)

d = 4 - 8

d = -4

Answer:  a = 3, b = 2, c = 0,d = -4

6 0
2 years ago
Read 2 more answers
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