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Olin [163]
1 year ago
13

How do you do this? I am really confused

Mathematics
1 answer:
german1 year ago
8 0

Answer:

Step-by-step explanation:

ok, so this is an infinitly repeating function, so you can write it as:

sqrt(12-x)

Although, x is also equal to sqrt(12-x), so

x = sqrt(12-x), and

x^2 = 12-x

x^2-12+x = 0

now just apply the quadratic formula and you're good

hope i helped :D

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What values of b satisfy 3(2b + 3)2 = 36?
KiRa [710]

the correct question is

What values of b satisfy 3(2b+3)^2 = 36


we have

3(2b+3)^2 = 36

Divide both sides by 3

(2b+3)^2 = 12

take the square root of both sides

( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3


b1=\frac{\sqrt{12}}{2} -\frac{3}{2}

b1=\sqrt{3} -\frac{3}{2}


b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}

therefore


the answer is

the values of b are

b1=\sqrt{3} -\frac{3}{2}

b2=-\sqrt{3} -\frac{3}{2}


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2 years ago
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Answer:

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