No, because you can simplify it even more if you divide by 2.
2/2=1
and 6/2=3
2/6 in simplest form is 1/3.
Let's call a child's ticket 
and an adult's ticket 
. From this, we can say:
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
.
Given these values, we can say:
,
since each adult ticket costs 17,000 and each child's ticket costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:
Let's solve:
- Find on its own, which will allow us to substitute it into the first equation
- Substitute in
for
- Apply the Distributive Property
- Subtract 1972000 from both sides of the equation and multiply both sides by -1
We have now found that 75 child's tickets were sold. Thus,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
R^2+(ab)^2= (ao)^2
ab=6
ao=11.7
Plug in
r^2+6^2=11.7^2
simplify
r^2+36= 136.89
-36 both sides
r^2=100.89
square root both sides
r= 10.04 rounded 10
Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
Rational numbers are numbers that can be written as the fraction of two integers. To multiply rational numbers together, simply the problem, then you multiply the tops and the bottoms separately to get your answer.
