If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
25,*55**3,552
*is the digit in the hundred thousand place
**is the digit that has 1/1000 the value of the digit.
(*) indicates the number after the *.
I doubled check this work, but I will update comment with a triple check
if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.
so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.
so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.
or using a unit vector for those above, then
T = 30h + 84l
C = h + 2l
P = h + 4l
C = 18h + 36l
P = 12h + 48l
