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Karo-lina-s [1.5K]
2 years ago
7

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Mathematics
1 answer:
Soloha48 [4]2 years ago
4 0

Answer:

9/36

Step-by-step explanation:

Given :1,2,3,4,5,6

first draw even probability 3/6=1/2

second draw even probability 3/6=1/2

1/2x1/2 or 3/6 x3/6= 1/4 or 9/36

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Rename 2934 as tens and ones
brilliants [131]
293 tens and 4 ones

<em>Explanation:
</em>If you have 293 tens you have 2930 already.
293*10 = 2930

Now you are only missing 4,
4*1 = 4
so you can use 4 ones
3 0
3 years ago
A cookie recipe states for every 3 cups of flour, 1 1/2 teaspoons of vanilla are needed. How many teaspoons are needed for 5 cup
skad [1K]
3 / 1½ = 2 cups of flour per teaspoon

2x = 5
divide both sides by 2 to isolate x

x = 2.5

You need 2.5 teaspoons of vanilla for 5 cups of flour.
4 0
3 years ago
Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant
alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z)  is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant  ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0
2 years ago
Suppose the base and height of a triangle sum to 18 cm, and the area of the triangle is 36 square cm. if the base is larger than
pentagon [3]
<span>15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:

a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)</span>
7 0
3 years ago
The perimeter of Dawna's new flat screen television is 112 inches. The ratio of its length to width is 4:3. Wire and solve an al
Dmitry_Shevchenko [17]
Hey there,
Length = 4x
Width = 3x
Perimeter = 112 inches
4x + 3x + 4x + 3x = 112 inches
14x = 112 inches
x = 112 inches / 14
   = 8 inches
Length = 8 inches x 4
            = 32 inches
Width = 8 inches x 3
          = 24 inches

 Hope this helps :))

<em>~Top♥</em>
5 0
3 years ago
Read 2 more answers
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