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BartSMP [9]
2 years ago
13

Can anyone help me as soon as possible??

Mathematics
1 answer:
matrenka [14]2 years ago
3 0

Answer:

X = 16

Step-by-step explanation:

Notice that we are in the presence of two similar triangles, one larger than the other. The larger triangle is AED, and the smaller one is ACB.

Since there are similar triangles, we can write a proportionality between their known sides:

\frac{side\,\,AD}{side\,\,AB} =\frac{side\,\,ED}{side \,\,CB}

notice that AD = x + 6

AB = x

ED = 11

CB = 8

So now we can re-write the proportion and solve it for the unknown "x":

\frac{side\,\,AD}{side\,\,AB} =\frac{side\,\,ED}{side \,\,CB} \\\\\frac{x+6}{x} =\frac{11}{8} \\8\,(x+6)=11\,x\\8\,x\,+\,48=11\,x\\48=11\,x-8\,x\\48=3\,x\\x=\frac{48}{3} \\x=16

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The graph below represents the following system of inequalities. y>x-2 y>2x+2 which points (x,y) satisfies the given syste
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Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.

The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!

Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.

y>x-2 -6> -4-2 -6= -6

That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.

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-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.

If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.

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Using the image given, the angles that are Alternate Exterior Angles are: 1, 2, 3, 4,13,14, 18, 19.

<h3>What are Alternate Exterior Angles?</h3>

These are known to be the Alternate exterior angles that are regarded as the pair of angles found on the outer side of the two parallel lines but they are seen on the opposite side of the transversal.

Note that in the image given, there are two parallel lines and two transversal lines.

Note also that to get the Alternate exterior angles, it has to be the angles seen on the seen on the opposite side of the transversal that has crossed the parallels lines and from the image given, only angle 1, 2, 3, 4,13,14, 18, 19 fit into the description.

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