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Mathematics

1 answer:

sleet_krkn [62]2 years ago

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Answer:

First box, second from the left,

Second box, first on the left.

Third box, third from the left.

Fourth box, Last on the right.

Step-by-step explanation:

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The lengths of a particular snake are approximately normally distributed with a given mean mu = 15 in. and standard deviation si

Helga [31]

The percentage of the snakes is longer than 16.6 in. with a mean of 15 in. and a standard deviation of 0.8 in. is 2.275%.

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The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in.

Then the percentage of the snakes is longer than 16.6 in. will be

$z = \dfrac{ x - \mu }{ \sigma }\\\\z = \dfrac{16.6-15}{0.8}\\\\z = 2$