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1 year ago

Can someone help me please

Mathematics

2 answers:

seraphim [82]1 year ago

6 0

Answer:

Area.

Step-by-step explanation:

2 dimentional spaces have only area, and no volume. Volume describes the amount of space within the container

MArishka [77]1 year ago

3 0

Answer: area

Step-by-step explanation:

Area is solved with L * W

Volume is solved with L * W * H

Using these formulas we can see that area uses 2-dimensions, the length and the width, while volume uses 3.

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What is an equation of the line that passes through the point ( 8 , − 4 ) and is parallel to the line x − 4 y = 12 x−4y=12?

Natasha2012 [34]

Answer:

as the line is parallel we do not change x-4y what we change is the result x = 8 & y = -4 so the result is 8 - 4 (-4) = 24 so the equation is 24

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2 years ago

John walks in the bearing of 75° and stops when he is 12 km North of his starting point.

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Circumference and area of 7ft

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2 years ago

The area of a circle is 2464cm2.calculate it's diameter to 2 significant figures<br>

tigry1 [53]

Answer:

Step-by-step explanation:

Answer:

The diameter of the circle is 56 cm.

Step-by-step explanation:

Given : The area of the circle is 2464 cm square.

To find : The diameter of the circle?

Solution :

The area of the circle is defined as

Where, A=2464 cm² is the area,

r is the radius

Substituting the values,

Radius of the circle is 28 cm.

The diameter of the circle is

Therefore, The diameter of the circle is 56 cm.

3 0

2 years ago

what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))

xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

$FG=9,GH=7,CD=24$

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}DE=FG$

$DE=2(FG)$

$DE=2(9)$

$DE=18$

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}CE=GH$

$CE=2(GH)$

$CE=2(7)$

$CE=14$

Now, the perimeter of the triangle CDE is:

$Perimeter=CD+DE+CE$

$Perimeter=24+18+14$

$Perimeter=56$

Therefore, the perimeter of the triangle CDE is 56 units.

7 0

2 years ago