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sergeinik [125]
2 years ago
9

Carly placed 50 marbles in a bag. Fifteen of the marbles are pink, 8 marbles are black,

Mathematics
1 answer:
yuradex [85]2 years ago
4 0

When you go into this problem, you want to figure out your marble ammount to 50 so in this case we will say C for color and 50 for the total ammount of marbles.

We know 15 are pink, 8 are black, 2 are green, 18 are clear, and 7 are striped

15P/50

8B/50

2G/50

18C/50

7S/50 for a total of 50 marbles

Now we use the chart to decide our awnsers  

A. We know our propability of drawing a green and clear is 20/50 which if we simplify is a 2/5 ratio. If We put this in perspective 2/5 is rare and is unlikley to even.

B. We know a striped marble is 18/50 or 1.8/5 ratio which is mainly unlikely

C. We have 23/50 marbles that are black and pink, our propability is about 2.3/5 and gives us an even chance to get one of these

D. We know we have 33/50 marbles that are pink and clear and gives us a 3.3/5 chance of getting one of  these and gives us an even to likely chance of getting one of these.

E. If we have a total of 17 marbles in these 3 colors, we have a 1.7/5 chance of getting one of these and is probably impossible to unlikey.

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If f(x) = -(1/x^3) and x takes on successive values from -10 to 0.1 ,
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Alright, this one is a little interesting... Let's perform some tests to figure out what is happening:
f(-10) = -(1/(-10)^3) = -(1/-1000) = 1/1000  (positive)
f(-5) = -(1/(-5)^3) = -(1/-125) = 1/125 (positive, bigger than the last one)
f(-1) = -(1/(-1)^3) = -(1/-1) = 1 (positive, bigger than the last one)
f(-0.1) = -(1/(-0.1)^3) = -(1/-0.001) = 1/0.001 = 1000 (positive, bigger than the last one)
f(0) = -(1/0^3) = undefined!
f(0.1) = -(1/(0.1)^3) = -(1/0.001) = -1/0.001 = -1000 (negative)
f(1) = -(1/1^3) = -(1/1) = -1 (negative, but bigger than last one)

It's a little confusing with the undefined part at x = 0. What I can say is this, it is increasing from -10 up to 0, something weird happens at 0 and it resets, and starts increasing from 0 up to 0.1. 

I guess A would be the best answer?

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